16y-30-2y^2=0

Solution for 16y-30-2y^2=0 equation:

16y-30-2y^2=0

a = -2; b = 16; c = -30;
Δ = b2-4ac
Δ = 162-4·(-2)·(-30)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4}{2*-2}=\frac{-20}{-4}
=+5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4}{2*-2}=\frac{-12}{-4}
=+3
$